Mathematics
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OpenStudy (anonymous):
Antidifferentiation help needed!
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OpenStudy (anonymous):
1. I don't get the concept behind finding the integral of 5x(1+ x^(2))^4
2. Also 2xe^(x)^(2)
3. How do you find the integral of sqrt(e^(x))?
OpenStudy (anonymous):
I need step by step for 3.
ganeshie8 (ganeshie8):
All these are u-substitution problems
OpenStudy (anonymous):
how?
ganeshie8 (ganeshie8):
if you understand how to work out one problems, others will be easy
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OpenStudy (anonymous):
okay
ganeshie8 (ganeshie8):
lets start with first problem
ganeshie8 (ganeshie8):
\(\large \int 5x(1+ x^2)^4 dx\)
ganeshie8 (ganeshie8):
substitute the stuff inside parenthesis as "u" :
\(\large u = 1+x^2\)
ganeshie8 (ganeshie8):
thats step 1
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ganeshie8 (ganeshie8):
step 2 : find out "dx" in terms of "du" :
\(\large u = 1+x^2\)
differentiate both sides
\(\large du = 2x dx\)
\(\large \frac{du}{2} = x dx\)
ganeshie8 (ganeshie8):
substitute these in the integral :
\(\large \int 5x(1+ x^2)^4 dx\)
becomes :
\(\large \int 5(u)^4 \frac{du}{2}\)
ganeshie8 (ganeshie8):
fine, so far ?
OpenStudy (anonymous):
?
ganeshie8 (ganeshie8):
? for which step ?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
no i get it now
OpenStudy (anonymous):
what about step 3?
ganeshie8 (ganeshie8):
how do u knw there are 3 steps ? :)
ganeshie8 (ganeshie8):
last step is to evaluate the integral and substitute back ur x
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OpenStudy (amistre64):
y = sqrt(e^x)
y^2 = e^x
y^3/3 = e^x + C
i wonder if this is appropriate :)
OpenStudy (amistre64):
its not lol
ganeshie8 (ganeshie8):
integral sign is missing lol
ganeshie8 (ganeshie8):
y = \int sqrt(e^x) dx
OpenStudy (anonymous):
?
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ganeshie8 (ganeshie8):
you wanto do the 3rd problem @AnImEfReaK ?
OpenStudy (anonymous):
i don't get it still
ganeshie8 (ganeshie8):
which one ?
you're still doing first problem ?
OpenStudy (anonymous):
yes is there a simpler method? i'm not familiar with du on its own. I have never done it that way or our class :/
ganeshie8 (ganeshie8):
what way you're doing in ur class ?
can u show an example problem ?
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ganeshie8 (ganeshie8):
mhm, lol i use to think u-substitution is an universal method
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
wait a moment
ganeshie8 (ganeshie8):
take ur time !
terenzreignz (terenzreignz):
I am intrigued :3