For the angle, name its quadrant and its reference angle.
Okay, seems rather straightforward...
I imagine you have lots of angles to do this with, am I right? XD
\[\theta= 460 degrees\]
Okay... nice to see you again too :/
yeah, but this one is kind of tricky, haha nice to see you, sorry I was trying to write the question lol.
I can see that. Do you have an example?
Well anyway, first, let's try to find which quadrant these buggers belong to, aye? ^_^
i don't have a way to show you the examples, pic doesn't come out clear... I think it's in quadrant II correct?
Yes. The only example I need is an answer concerning the reference angle, just to make sure we're on the same page.
wait what's the question you're asking? haha
Never mind. Okay, 460 degrees is in the second quadrant, okay, that's good. How did you get that?
well I know one full rotation is 360 degrees, 90 each quadrant. so 360 degrees + quadrant I + 10 degrees, would enter quadrant II
and it's positive so it rotates to the left.
Well, if that way works for you, then what's the problem? Reference angle? :)
yes, I'm trying to find the reference angle.
Well, first, you need to find the coterminal angle that lies between 0 and 360. So for 460, what is it?
If it's positive, here's a hint... just divide by 360, and get the remainder.
hmm.. is it 100?
Yup. Now, if you know this coterminal angle, and you know its quadrant, then the reference angle should be easy. If let let A be that coterminal angle, then... -If it's in QI, then the reference angle is A. -If it's in Q2, then the reference angle is 180 - A -If it's in Q3, then the reference angle is A - 180 -If it's in Q4, then the reference angle is 360 - A. So, what's the reference angle of 460 degrees? ^_^
80 degrees!
Yup. There we go ^_^
thanks for the help @terenzreignz !! ☺
TJ dammit. It's TJ >:(
And it goes without saying, but I'll say it anyway, but be EXTRA CAREFUL when finding that reference angle. It should always be between 0 and 90. ALWAYS.
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