Find the roots of the polynomial equation.

x2 + 2x – 48 = 0

A.
–6, 8

B.
–4, 12

C.
–12, –4

D.
–8, 6

@elissaab

Question

Find the roots of the polynomial equation.
 
        x2 + 2x – 48 = 0
 
 
 A.
–6, 8
 
 B.
–4, 12
 
 C.
–12, –4
 
 D.
–8, 6


@elissaab

anonymous · Answer

@eliassaab

anonymous · Answer

$$\frac{ -b \pm \sqrt{b^2-4*a*c} }{ 2a }$$

anonymous · Answer

does that look familiar to you?

mathmale · Answer

x2 + 2x – 48 = 0, or $$  x^2 + 2x – 48 = 0$$  is a quadratic equation.  Each of the three terms on the left has a constant coefficient.  What are the three coefficients, a, b and c?  Once you've identified those, plug them into the quadratic formula, as given you by zimmah, above, and determine the values of the roots of this quadratic equation.

anonymous · Answer

In this case by the way there is an easier method, but it's not always as easy.

you can try to find two numbers so that:
1) when you add up these two numbers they make +2
2) when you multiply these two numbers they make -48

anonymous · Answer

Since you tagged me, here is a hint http://www.wolframalpha.com/input/?i=factor++x%5E2+%2B+2x+%E2%80%93+48