Question

find the missing dimension of the cone. round to nerest tenth...volume=1/18 pi ft^3

Answer 1

help please

Answer 2

sorry it show the bottom is 2/3 completely across

Answer 3

so 1/3 right?

Answer 4

The radius?

Answer 5

yes. missing height

Answer 6

and one more and I'll post after

Answer 7

Well let's work backwards..
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\[\LARGE \frac{1}{18} \pi= \pi r^2 \frac{h}{3}\]

Answer 8

And you said 2/3 was all the way across?

Answer 9

yes

Answer 10

So yea, 1/3=r

Plug that in too..
\[\LARGE \frac{1}{18} \pi= \pi (\frac{1}{3})^2 \frac{h}{3}\]
Simpify it
\[\LARGE \frac{1}{18} \pi= \frac{\pi h}{18}\]

Answer 11

Can you finish from here?

Answer 12

umm can you help?

Answer 13

not real good at math

Answer 14

We have
\[\LARGE \frac{\pi}{18}= \frac{\pi h}{18}\]
We just multiply by the reciprocal like so..
\[\LARGE \frac{\pi}{18}*\frac{18}{\pi} = \frac{\pi h}{18}*\frac{18}{\pi}\]
That'll cancel the \(\frac{\pi}{18}\) and get \(h\) by itself
Leaaving us with this nice height of \(\large h=1\) :)

Answer 15

thank you sooo much :)

Answer 16

You're welcome ^_^