Question

how do I factor 81c^2-16

Answer 1

what number squared is 16?

Answer 2

4 right

Answer 3

right
and what would you square to get \(81c^2\) ?

Answer 4

umm 9c^2

Answer 5

well actually \(9c\)

Answer 6

since \((9c)^2=81c^2\)

Answer 7

now factor the difference of two squares as
\[a^2-b^2=(a+b)(a-b)\] with \(a=9c\) and \(b=4\)

Answer 8

is it 65 = (9+4) (9-4) right

Answer 9

there is no 65 in the question, and you are missing a c

Answer 10

\[81c^2-16=(9c+4)(9c-4)\]

Answer 11

what do I do now I am lost

Answer 12

hello there

Answer 13

help me please