10. You have six $1 bills, eight $5 bills, and four $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?
A. 77/190
B. 3/100
C. 3/95
D. 2/5
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OpenStudy (anonymous):
just a question what grade r u in
OpenStudy (anonymous):
I'm in 8th
OpenStudy (anonymous):
no wonder i dont understand
OpenStudy (anonymous):
CX
OpenStudy (anonymous):
wow im usualy great at this kind of stuff
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OpenStudy (anonymous):
I don't understand this either. C:
OpenStudy (anonymous):
@OrangeMaster
OpenStudy (anonymous):
I don't see any $10 bills in the word problem.
OpenStudy (anonymous):
thats what got me too
OpenStudy (anonymous):
OH oops. I missed that. You have six $1 bills, eight $5 bills, two $10 bills, and four $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?
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OpenStudy (anonymous):
Thanks for noticing
OpenStudy (anonymous):
i still dont get it and i have a math book right beside me
OpenStudy (anonymous):
Probability from one dollar bills: 3/10
Probability of 10 dollar bills: 2/19\[\frac{ 3 }{ 10 }\times \frac{ 2 }{ 19 }\]
OpenStudy (anonymous):
So, it's C?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Thank you so much!
OpenStudy (anonymous):
Your welcome. :)
OpenStudy (anonymous):
your welcome ^-^
OpenStudy (anonymous):
X)
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