Question

what is the wind chill with T=-10 cel and V=20m/sec.. using the wind formula?
w=33-(10.45+10squV-V)(33-T)/22 @mathmale

Answer 1

We're given the wind formula: \[ w=33-(10.45+10\sqrt{V} V-V)(33-T)/22\]. I'm not convinced this is correct. Please compare this to the original equation and let me know if my interpretation is incorrect.

Answer 2

@mathmale the only thing that is wrong with the formula is that it should be one V under the \[\sqrt{v}\]

Answer 3

So, is the following correct?\[w=33-(10.45+10\sqrt{V} -V)(33-T)/22?\] sorry this is taking so long, but until we're both sure we have the formula correct, there's no point in trying to evaluate it at some numeric value. If you were given this problem online, would you please take a screen shot of the original problem statement and share it with me?

Answer 4

No it's okay.. thanks for the help.. the formula you just wrote is correct.
T=-10 V=20 @mathmale

Answer 5

OK: You are asked, "what is the wind chill with T=-10 cel and V=20m/sec.?" Just substitute these values of T and V into the equation.

Answer 6

yes can you should me it worked out? because I think I did a step wrong.

Answer 7

\[w=33-(10.45+10\sqrt{V} -V)(33-T)/22 ~when~T=-10 ~and~V=\frac{ 20 m }{ \sec }\]

Answer 8

Let's evaluate this formula piece by piece. First, your (10.45 + 10 Sqrt(v) - V) becomes
10.45 + 10Sqrt(20m/sec) -20m/sec.

This does not look right to me because the units of measurement are not consistent.

Answer 9

(33-T) when T=-10 would be

(33-[-10]) = 33+10=43.

Answer 10

Again, I see inconsistencies in the units of measurement, and again encourage you to share a screen shot of the original problem.

Answer 11

How do I screen shot it?

Answer 12

First, in what material did you find this problem? If you're not sure how to take a screen shot, please just forward the URL of the online material in which you found the problem.

How one takes a screen shot depends upon what computer and what software one has.

Answer 13

4) The formula to find the wind chill temperature is given by
Where,
W is Wind Chill temperature (temperature with no wind)
T is actual temperature in Celcius
V is wind speeds in m/sec
Find the Wind Chill temperature given the following:

T =-10 , v = 20m/sec

Answer 14

Just used the formula that you typed..

Answer 15

Thanks. Still need to see the original formula. If you have a cell phone, consider taking a picture of the original formula and sharing the image with me.

Alternatively, would YOU please substitute the given values into the formula, showing me your work? If necessary, use the Draw utility (below).

Answer 16

I'm sorry, but as I explained earlier, I have my doubts that my interpretation of your formula is correct. Next week, in school, please ask a teacher or a friend to demonstrate for you how to take screen shots. Again, if you have a cell phone that can take photos, you have an alternative method for sharing images.

Answer 17

@mathmale: You may wish to refer to the following URL for evaluating the discrepancy between this formula and the original model:

http://en.wikipedia.org/wiki/Wind_chill

Answer 18

Yes that is the formula that @shiraz14 just shared with us from Wiki.. the orginial format @mathmale . Do you know how to do this @shiraz14 ?

Answer 19

@t.street17 : It's like what @mathmale has posted - you just need to substitute the values. @mathmale : I understand where you are coming from but I presume that we should just assume that they are dimensionless constants (to avoid confusion for now) ...

Answer 20

@shiraaz14: It was VERY helpful of you to look up and share this formula. Thank you very much!

Answer 21

@mathmale : You're most welcome.

Answer 22

Given that V=20m/sec, please evaluate \[(10\sqrt{V}-V+10.5).\]Please show your work.

Answer 23

I just did that and I got 68.74 for the answer

Answer 24

Next, given that T=-10 degrees Celcius, please evaluate\[33-T _{a}\]

Answer 25

did you get the same answer I got @mathmale of 68.74?

Answer 26

I haven't been calculating those myself, since I'm assuming you can do that. But in this case I'll check. Please more on to evaluating the other expression (see above).

Answer 27

Yeah I have done all of that ... I am just checking my answer now

Answer 28

My evaluation of \[(10\sqrt{V}-V+10.5)\] comes out to 35.22:

Answer 29

mine was 35.17... let me check it

Answer 30

\[10\sqrt{20}-20+10.5=44.72 - 20 + 10.5 = 24.72+10.5 = 35.22\]

Answer 31

I'd say your 35.17 is close enough.

Answer 32

Now, what about\[35-T _{a}?\]

Answer 33

okay .... I think I am have the answer... this is making my head hurt... lol.. thanks for your help

Answer 34

@mathmale : I think there's a typo - it should be 33 - Ta?

Answer 35

I'm so glad we've reached closure on this. Again, I'd suggest you ask around at school for help in taking screen shots, or experiment with taking and sharing images of your written work with your cell phone (assuming you have one). Sharing images would have made this conversation go a lot faster. Best of luck to you! And once again, thank you, @shiraz14!

Answer 36

@shiraz14: again, you are correct. Thanks! I'm going to hire you as my consultant.

Answer 37

@mathmale : ;)

Answer 38

@t.street17 & @mathmale : There's only a slight variation between the model provided in the Wiki and the one provided by @t.street17 earlier. @t.street17, are you certain that this is the same formula provided in your worksheet? Or is the formula the same as the one in the Wiki?

Answer 39

I noticed, also, that there are differences between t.street's formula and that provided in the Wiki. This is why I felt it so important to ask for an illustration of the problem you (@t.street) were working on. Your (@t.street's) formula includes division by 22 which is not a part of the Wiki-provided formula.

Answer 40

@mathmale : Yes, you're correct.

Answer 41

Goodbye for now