The physics department of a college has 9 male professors, 8 female professors, 10 male teaching assistants, and 13 female teaching assistants. If a person is selected at random from the group, find the probability that the selected person is a teaching assistant or a female.
Number who are teaching assistants and/or female 10 + 13 + 8 ------------------------------------------ = ------------------ Total Number of People 9 + 8 + 10 + 13
BG: Would you mind typing out the formula used to calculate P(A or B), when P(A), P(B) and P(A AND B) are given?
In my opinion, students should not automatically think "Which formula do I need for this?" I tend not to explain things that way. For many it makes intuitive sense to do these applying the concept. Number of things we want ---------------------- Total number of things we're choosing from
My result is dramatically different from yours: \[\frac{ 23 }{ 40 }+\frac{ 21 }{ 40 }-\frac{ 13 }{ 40 }=\frac{ ? }{ 40 }\]
So long as we arrive at the same answers, I'm not so concerned about using a formula versus using an intuitive approach.
BG: I first set up a contingency table, which made it easy to determine P(TA), P(F) and P(TA and F).
@Elaina928: May we hear from you, please? It's important that you be involved in finding the solution to what is, after all, your math problem.
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