Question

I really need help understanding how to do this. I will give medal and become a fan if you help me. :)

Answer 1

\[\large 8^{x-2}=3\]?

Answer 2

Yes

Answer 3

for this you need two things
1) the change of base formula which says
\[\large b^x=y\iff x=\frac{\log(y)}{\log(b)}\] and
2) a calculator

Answer 4

\[\large 8^{2-x}=3\iff 2-x=\frac{\log(3)}{\log(8)}\] solve for \(x\) and using algebra, then use a calculator to get the numeric answer

Answer 5

you good from there?

Answer 6

So I would do log(3)/log(8) which gets .53 - 2 that gets -1.47 and then multiply it be -1 to get 1.47?

Answer 7

yes i guess so
i would do the algebra first, but either way should do it

Answer 8

\[x=2-\frac{\log(3)}{\log(8)}\] which is what you got too

Answer 9

Okay thank you so much

Answer 10

yw