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OpenStudy (anonymous):
PLEASE HELP 2. What is the molarity of a 5.00 x 102 ml solution containing 2490 g of KI? 3. How many moles of LiF would be required to produce a 2.5 M solution with a volume of 10.5 L?
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OpenStudy (anonymous):
Molarity= mass of KI / molar mass of KI X 1000 / Vol in ml
OpenStudy (anonymous):
molar mass of KI=39+127=166 Ans will be 30 molar
OpenStudy (anonymous):
Molarity = moles / Vol in Liter rearange it: moles = molarity X vol in L moles = 2.5 X 10.5 = 26.25 moles of LiF is required
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