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Chemistry 9 Online
OpenStudy (anonymous):

PLEASE HELP 2. What is the molarity of a 5.00 x 102 ml solution containing 2490 g of KI? 3. How many moles of LiF would be required to produce a 2.5 M solution with a volume of 10.5 L?

OpenStudy (anonymous):

Molarity= mass of KI / molar mass of KI X 1000 / Vol in ml

OpenStudy (anonymous):

molar mass of KI=39+127=166 Ans will be 30 molar

OpenStudy (anonymous):

Molarity = moles / Vol in Liter rearange it: moles = molarity X vol in L moles = 2.5 X 10.5 = 26.25 moles of LiF is required

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