Question

PLEASE HELP

2. What is the molarity of a 5.00 x 102 ml solution containing 2490 g of KI?



3. How many moles of LiF would be required to produce a 2.5 M solution with a volume of 10.5 L?

Answer 1

Molarity= mass of KI / molar mass of KI X 1000 / Vol in ml

Answer 2

molar mass of KI=39+127=166
Ans will be 30 molar

Answer 3

Molarity = moles / Vol in Liter
rearange it:
moles = molarity X vol in L
moles = 2.5 X 10.5 = 26.25 moles of LiF is required