Question

16t^2+14t-15=0

Answer 1

do you know quadratic formula ?

Answer 2

You have to use ax^2+bx+c=0

Answer 3

Compare your quadratic equation with \(at^2+bt+c=0\)
find \[a=...?\\b=...?\\c=...?\\\] \[ \\ \sqrt{b^2-4ac}=...?\]
then the two roots of t are:
\(\huge{t_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

Answer 4

ok

Answer 5

first step is to find
a=...?
b= ...?
c=... ?

Answer 6

a= 1
b= 4
c=3

Answer 7

how did you get those? is your equation, \(t^2+4t+3-0 \) ??