Question

express as a single logarithm
3log(a)(2x+1)-2log(a)(2x-1)+2

Answer 1

\[3Log_a(2x+1)-2Log_a(2x-1)+2\]

Is that correct?

If so, you're first step should be to use your rules for logs and make the coefficients (the numbers out front) into exponents for whats inside the log.

Answer 2

yes thats correct

Answer 3

Do you know how to rewrite the logs so that the coefficients become exponents?

\[aLog(x) = Log(x^a)\]

Answer 4

no

Answer 5

I'll do the first log in your question, to show what I'm saying. You do the second:

\[3Log_a(2x+1) = Log_a[(2x+1)^3]\]

You try with the second log.

Answer 6

idk what to do next

Answer 7

What did you get?

Answer 8

i don't know how to do it