Question

PLEASE HELP!! Thank you!! :)

There are 9 red gumballs, 5 green gumballs, 8 yellow gumballs, and 8 blue gumballs in a machine. Find P(green then yellow).

A. 40/900
B. 5/30
C. 8/30
D. 40/870

Answer 1

How do we find the probability of getting a green gum ball first?

Answer 2

I think you find the sum of total gumballs in the machine, which is 30. Sorry I'm noot good at this :p

Answer 3

most likely its B

Answer 4

Right. Number of Green / Total Number = Probability of drawing a green first

Answer 5

Now, after this, we've removed one green gumball. So now we only have 4 green in the machine, and 29 total in the machine. What's the probability of now drawing a yellow gum ball?

Answer 6

8/29

Answer 7

oh sorry I was wrong! lmao! please forgive me

Answer 8

Good!

Now, P(A then B) = P(A)*P(B)

So we can calculate the probability of these two events happening one after the other.

Answer 9

Lol it's fine @Xx_J.L.S_Xx Okay so P(5)*P(8)?

Answer 10

Use the probabilities we found:

P(Green first) = 5/30
P(Yellow second) = 8/29

Answer 11

Oh, okay. Will brb gonna solve this. Lol

Answer 12

Okay, I can't figure it out lol... Help?

Answer 13

Watt nevermind! I got it it's 40/870 :)

Answer 14

@Vandreigan he needs your help.

Answer 15

oh ok :D good job!

Answer 16

thanks for the medal!

Answer 17

Thanks. Haha. Thanks for helping. :) thank you @Vandreigan :) you're welcome