Question

Factor 3x^2y^2 - xy^2 - 2y^2

Answer 1

I belive that the answer is 3x - 2

Answer 2

First pull the GCF out

Answer 3

you have 3 terms,
whats the common factor ? (if exists)

Answer 4

its xy^2 right?

Answer 5

*last term have no x-terms

Answer 6

Oh right so only y^2

Answer 7

Yep, pull that out

Answer 8

3x^2 - x - 2

Answer 9

3x^2y^2 - xy^2 - 2y^2

y^2( 3x^2 - x - 2 )

Answer 10

So now wouldn't that be the answer 3x^2 -x - 2

Answer 11

I believe that you cant do anything else to it

Answer 12

you can still factor 3x^2 - x - 2

Answer 13

Huh but by what?

Answer 14

factor by grouping

Answer 15

pick any two number such that :
they multiply to -6
add up to -1

Answer 16

umm -3 and -2?

Answer 17

Or postive 3 and negative 2

Answer 18

+3 -2 is not -1

Answer 19

What do you so with those numbers now?

Answer 20

the magic numbers are -3 and +2 :

-3*2 = -6
-3 + 2 = -1

Answer 21

what do i do with -3 and +2 when i have them

Answer 22

3x^2 - x - 2


split the second term as : -3x + 2x

Answer 23

3x^2 - x - 2

3x^2 - 3x + 2x - 2

Answer 24

factor the GCF from first two terms and last two terms separately

Answer 25

3x^2 - x - 2

3x^2 - 3x + 2x - 2

3x(x-1) + 2(x-1)

(x-1)(3x+2)

Answer 26

the final factorization is :

3x^2y^2 - xy^2 - 2y^2 = y^2(x-1)(3x+2)

Answer 27

Wouldn't that be (3x + 2)(x - 1)

Answer 28

yes, both are same

Answer 29

the final answer is ` y^2(x-1)(3x+2)`

you must include `y^2` also, okay ?

Answer 30

Same thing, multiplication is commutative, order doesn't matter >.>

Answer 31

Know what if you cant do the simplfying like in this umm
x^2 + 6x + 9

Answer 32

Perfect square?

(x + 3)^2 = (x)^2 + 2(x)(3) + (3)^2

Or,

(x+3)(x+3) = x^2 + 3x + 3x + 9 = x^2 + 6x + 9

Answer 33

Thank you guys :) Have a great day

Answer 34

Yw :>