(√(2m)^-3)/(m^-1)
do you want to clear for m?
I want to simplify.
ok so \[\frac{ \sqrt{2m}^{-3} }{ m ^{-1} }\]
The 2m is in parentheses.
@Ashy98 you know you have to use your brain?
yeah, thats why the root is working for the whole thing
\[√(2m)^-3\]
yeah @SalvadorV but that helps just a little!
you start by passing the m^-1 which is dividing, up as m^1 or just m
well, this is to learn, not just to have someone finish your homework @Ashy98
a1234, if the sqrt is being applied to 2m, it is the same as having it in a parentheses
Won't 2^3 be done then?
Because I thought (2m)^3 is 8m^3.
so we have then \[\sqrt{2m}^3*m\], no because the square root has the same priority as the power and is written first
what you say would be sqrt((2m)^3)
That's what I'm saying, sqrt((2m)^3).
and would be written this way \[\sqrt{(2m)^3}\]
Yup, that way
i thought you were supposed to be nice to people on this site? @SalvadorV
sorry, I didn't mean to be rude
so we have to simplify (2m)^-3=1/(2m)^3=1/8m^3 and we`d have \[\sqrt{\frac{ 1 }{ 8 }m^{-3}}*m\]
In that case, should it be -3 or 3?
and then we can take the sqrt as an exponent to simplify like \[\sqrt{\frac{ 1 }{ 8 }m ^{-3}}*m=\sqrt{\frac{ 1 }{ 8 }}*\sqrt{m ^{-3}}*m=\sqrt{\frac{ 1 }{ 8 }}*m ^{-3/2}*m\]
well,it's -3 in the first place right?
Yes, but if we do 1/((2m)^3). That's how you'd eventually get 1/8, right?
no, the 1/8 is because its -3, if it was 3 it would be 8m^3
Aah...yes, I see now.
what you do is make the (2m)^-3=1/2m^3
thats how you get it
do you want me to continue or do you need any further explaining?
I think I get it.
then you see I separate the 1/8 and the m^-3 because when you are making the sqrt of a product is the same as the product of the sqrts
\[\sqrt{ab}=\sqrt{a}*\sqrt{b}\]
Thanks for all the help!
heeey hold your horses, we haven't finished
we can still simplify one thing
*I mean the help, not all the help :). Yes, I know we're not done.
hahaha you're welcome C:
so, we have that \[\sqrt\frac{ 1 }{ 8 }*m ^{-3/2}*m\]
what happens when you multiply 2 values that have the same base but differnt exponents?
The exponents add up.
exactly, so we have\[m ^{-3/2}*m^1=m ^{(-3/2)+1}=m ^{1/2}\]
sorry, -1/2
and then we put it back to its sqrt form and simplify
\[\sqrt{\frac{ 1 }{ 8 }}*m ^{-1/2}=\sqrt{\frac{ 1 }{ 8 }}\sqrt{m ^{-1}}\]
here we use the same rule for the product of the sqrt as follows\[previous..thingy=\sqrt{\frac{ 1 }{ 8 }m ^{-1}}=\sqrt{\frac{ 1 }{ 8 }*\frac{ 1 }{ m }}=\sqrt{\frac{ 1 }{ 8m }}\]
Yes, and we can still simplify that, right?
Because 8m can be sqrt4 * 2m.
* sqrt2m
I don't think so.... how would you do that?
\[1/\sqrt{4}*\sqrt{2m}\]
By the way, the answer key says (sqrt2m)/4m as the answer.
well I guess but I don't believe that's simpler xD
I don't know how they get that final answer...
can you use the equation button to plug in exactly how it looks like?
\[\sqrt{2m}/4m\]
Sqrt2m is the numerator and 4m is the denominator.
okay, how does the first equation look, the one from which we started
Never mind, I figured it out.
okay
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