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Mathematics 9 Online
OpenStudy (a1234):

(√(2m)^-3)/(m^-1)

OpenStudy (anonymous):

do you want to clear for m?

OpenStudy (a1234):

I want to simplify.

OpenStudy (anonymous):

ok so \[\frac{ \sqrt{2m}^{-3} }{ m ^{-1} }\]

OpenStudy (a1234):

The 2m is in parentheses.

OpenStudy (anonymous):

@Ashy98 you know you have to use your brain?

OpenStudy (anonymous):

yeah, thats why the root is working for the whole thing

OpenStudy (a1234):

\[√(2m)^-3\]

OpenStudy (ashy98):

yeah @SalvadorV but that helps just a little!

OpenStudy (anonymous):

you start by passing the m^-1 which is dividing, up as m^1 or just m

OpenStudy (anonymous):

well, this is to learn, not just to have someone finish your homework @Ashy98

OpenStudy (anonymous):

a1234, if the sqrt is being applied to 2m, it is the same as having it in a parentheses

OpenStudy (a1234):

Won't 2^3 be done then?

OpenStudy (a1234):

Because I thought (2m)^3 is 8m^3.

OpenStudy (anonymous):

so we have then \[\sqrt{2m}^3*m\], no because the square root has the same priority as the power and is written first

OpenStudy (anonymous):

what you say would be sqrt((2m)^3)

OpenStudy (a1234):

That's what I'm saying, sqrt((2m)^3).

OpenStudy (anonymous):

and would be written this way \[\sqrt{(2m)^3}\]

OpenStudy (a1234):

Yup, that way

OpenStudy (ashy98):

i thought you were supposed to be nice to people on this site? @SalvadorV

OpenStudy (anonymous):

sorry, I didn't mean to be rude

OpenStudy (anonymous):

so we have to simplify (2m)^-3=1/(2m)^3=1/8m^3 and we`d have \[\sqrt{\frac{ 1 }{ 8 }m^{-3}}*m\]

OpenStudy (a1234):

In that case, should it be -3 or 3?

OpenStudy (anonymous):

and then we can take the sqrt as an exponent to simplify like \[\sqrt{\frac{ 1 }{ 8 }m ^{-3}}*m=\sqrt{\frac{ 1 }{ 8 }}*\sqrt{m ^{-3}}*m=\sqrt{\frac{ 1 }{ 8 }}*m ^{-3/2}*m\]

OpenStudy (anonymous):

well,it's -3 in the first place right?

OpenStudy (a1234):

Yes, but if we do 1/((2m)^3). That's how you'd eventually get 1/8, right?

OpenStudy (anonymous):

no, the 1/8 is because its -3, if it was 3 it would be 8m^3

OpenStudy (a1234):

Aah...yes, I see now.

OpenStudy (anonymous):

what you do is make the (2m)^-3=1/2m^3

OpenStudy (anonymous):

thats how you get it

OpenStudy (anonymous):

do you want me to continue or do you need any further explaining?

OpenStudy (a1234):

I think I get it.

OpenStudy (anonymous):

then you see I separate the 1/8 and the m^-3 because when you are making the sqrt of a product is the same as the product of the sqrts

OpenStudy (anonymous):

\[\sqrt{ab}=\sqrt{a}*\sqrt{b}\]

OpenStudy (a1234):

Thanks for all the help!

OpenStudy (anonymous):

heeey hold your horses, we haven't finished

OpenStudy (anonymous):

we can still simplify one thing

OpenStudy (a1234):

*I mean the help, not all the help :). Yes, I know we're not done.

OpenStudy (anonymous):

hahaha you're welcome C:

OpenStudy (anonymous):

so, we have that \[\sqrt\frac{ 1 }{ 8 }*m ^{-3/2}*m\]

OpenStudy (anonymous):

what happens when you multiply 2 values that have the same base but differnt exponents?

OpenStudy (a1234):

The exponents add up.

OpenStudy (anonymous):

exactly, so we have\[m ^{-3/2}*m^1=m ^{(-3/2)+1}=m ^{1/2}\]

OpenStudy (anonymous):

sorry, -1/2

OpenStudy (anonymous):

and then we put it back to its sqrt form and simplify

OpenStudy (anonymous):

\[\sqrt{\frac{ 1 }{ 8 }}*m ^{-1/2}=\sqrt{\frac{ 1 }{ 8 }}\sqrt{m ^{-1}}\]

OpenStudy (anonymous):

here we use the same rule for the product of the sqrt as follows\[previous..thingy=\sqrt{\frac{ 1 }{ 8 }m ^{-1}}=\sqrt{\frac{ 1 }{ 8 }*\frac{ 1 }{ m }}=\sqrt{\frac{ 1 }{ 8m }}\]

OpenStudy (a1234):

Yes, and we can still simplify that, right?

OpenStudy (a1234):

Because 8m can be sqrt4 * 2m.

OpenStudy (a1234):

* sqrt2m

OpenStudy (anonymous):

I don't think so.... how would you do that?

OpenStudy (a1234):

\[1/\sqrt{4}*\sqrt{2m}\]

OpenStudy (a1234):

By the way, the answer key says (sqrt2m)/4m as the answer.

OpenStudy (anonymous):

well I guess but I don't believe that's simpler xD

OpenStudy (a1234):

I don't know how they get that final answer...

OpenStudy (anonymous):

can you use the equation button to plug in exactly how it looks like?

OpenStudy (a1234):

\[\sqrt{2m}/4m\]

OpenStudy (a1234):

Sqrt2m is the numerator and 4m is the denominator.

OpenStudy (anonymous):

okay, how does the first equation look, the one from which we started

OpenStudy (a1234):

Never mind, I figured it out.

OpenStudy (anonymous):

okay

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