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Mathematics 51 Online
OpenStudy (anonymous):

Pizza Time has collected data about customer pizza topping preferences. They have calculated that P(pepperoni) = 0.7, P(olives) = 0.6, and P(pepperoni or olives) = 0.8. Determine the P(pepperoni and olives).

OpenStudy (anonymous):

0.4 0.5 0.6 0.7

OpenStudy (anonymous):

\[.7+.6-P(A\cap B)=.8\]

OpenStudy (anonymous):

I don't get which numbers should be substituted for P, A and B...?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@satellite73 lol whats the answer?

OpenStudy (anonymous):

??

OpenStudy (anonymous):

where did you find this piece of ancient history?

OpenStudy (anonymous):

hahah i have the same question LOOL

OpenStudy (anonymous):

exact same numbers and everything?

OpenStudy (anonymous):

check it

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[.7+.6-P(A\cap B)=.8\] solve for \(P(A\cap B)\) i am sure you can do that what is \(.7+.6\) ?

OpenStudy (anonymous):

1.3

OpenStudy (anonymous):

ok and \(1.3-.8\) ?

OpenStudy (anonymous):

.5

OpenStudy (anonymous):

that is it

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

lol yw

OpenStudy (juanpablojr):

Even more ancient for me lol :) @satellite73

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