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Mathematics 6 Online
OpenStudy (anonymous):

20e^3x=100

OpenStudy (anonymous):

and another problem is 2^5x=24

OpenStudy (anonymous):

2

OpenStudy (anonymous):

its not 2

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

-1.6

OpenStudy (anonymous):

for the 2nd question

OpenStudy (anonymous):

i need all work

OpenStudy (johnweldon1993):

For the first one... Start off by dividing both sides by 20 to get the 'e' by itself \[\large e^{3x} = 5\] Take the natural log of both sides \[\large \ln(e^{3x}) = \ln(5)\] \[\large 3x = \ln(5)\] \[\large x = \frac{\ln(5)}{3}\] Second problem just like that

OpenStudy (anonymous):

can you solve second

OpenStudy (anonymous):

just bc it doesnt have e its confusing

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