Question

Helppp!! me!!

Answer 1

hi?

Answer 2

whaddya need help with

Answer 3

it says "multiply and simplify" but that is not what it really means
it means "factor and cancel"
factor the top and bottom, cancel the common factors

Answer 4

\[\frac{x^2-4}{x^2-1}\times \frac{x+1}{x+2}\]
\[=\frac{(x+2)(x-2)(x+1)}{(x+1)(x-1)(x+2}\]
cancel the common factors

Answer 5

for some reason math teachers like to lie
there is no multiplication going on here at all
nor is there such a thing as 'simplify"
it means reduce
\[=\frac{(x+2)(x-2)(x+1)}{(x+1)(x-1)(x+2)}=\frac{\cancel{(x+2)}(x-2)\cancel{(x+1)}}{\cancel{(x+1)}(x-1)\cancel{(x+2)}}=\frac{x-2}{x-1}\]

Answer 6

thank you so much it always confusses me. lol

Answer 7

yw
other one works the same way

Answer 8

ok..

Answer 9

in that case the denominator factors as \((x+3)(x+4)\) so everything goes, leaving only \(\frac{1}{x}\)