Question

How many different 4-digit sequences can be formed using the digits 0, 1,..., 6 if repetition of digits is allowed?
a.
1296
c.
24
b.
20
d.
2401

Answer 1

First, identify how many different "choices" you have for each digit of the 4 digit number.

Answer 2

its 7x7x7x7

Answer 3

2041

Answer 4

There ya go.

Answer 5

thanks for you help :)

Answer 6

My pleasure :)

Answer 7

A card is picked at random from a standard deck of cards. What is the sample space for this experiment if you were trying to find P(face card)?

Answer 8

@Ashleyisakitty @austinL @adrynicoleb @annas @Abdulhameed @bbcream14 @Biokiiller396

Answer 9

@Compassionate @Vandreigan

Answer 10

im sorry i dont no this one but i can get some people who can help you

Answer 11

@Whitemonsterbunny17 @TheOcean @elementwielder

Answer 12

I'm trying to remember the exact definition of sample space. I could calculate P(face), but I'm not certain of how to answer this, off the top of my head.

Answer 13

I guess you'd define the sample space as {face card, not a face card}, since we're only interested in whether it's a face card or not.

Answer 14

In a certain lottery, 5 numbers between 1 and 13 inclusive are drawn. These are the winning numbers. How many different selections are possible? Assume that the order in which the numbers are drawn is not important.
a.
1287
c.
371,293
b.
154,440
d.
120

Answer 15

what about this one?

Answer 16

I'm assuming this is without replacement.

Use the binomial coefficient:
\[\left(\begin{matrix}N \\ k\end{matrix}\right) = \frac{N!}{k!(N-k)!}\]

This gives you the number of possible ways to choose k different things from set of size N.

In your case, you want to choose 5 numbers from a set of 13 numbers.