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Mathematics 8 Online
OpenStudy (anonymous):

Which is more likely to occur (i.e. has a higher probability): a. Rolling a 2 or higher on a single 6 sided die b. Rolling a 3 or higher on a single 6 sided die, if you can re-roll the die if you fail the first time

OpenStudy (anonymous):

First, what's the probability of getting a 2 or higher on a 6 sided die?

OpenStudy (anonymous):

5/6

OpenStudy (anonymous):

Ok, so the tricky part is 3 or higher on one of two rolls. Since we don't really care about the second roll if the first one hits, we don't need to limit ourselves to only a single hit. What this means is that we should find the probability to NOT get a 3 or higher on a die after two rolls, and subtract that from one. What's the probability to NOT get a 3 or higher on a 6 sided die after one roll?

OpenStudy (anonymous):

33.2%

OpenStudy (anonymous):

or 33% i don't know why i put a .2

OpenStudy (anonymous):

2/6 or 1/3, right. So, the chance to fail to get a 3 or higher on the first roll is 1/3. It's the same on the second. \[P(AandB)=P(A)P(B)\] So what is the probability of rolling twice and neither roll being 3 or higher?

OpenStudy (anonymous):

so you just multiply them 1/3 times 1/3

OpenStudy (anonymous):

Correct. That gives the chance to NOT get a 3 or higher on either roll.

OpenStudy (anonymous):

so 1/9

OpenStudy (anonymous):

Right. So if the chance to NOT roll a 3 or higher is 1/9, then what is the chance to roll a 3 or higher at least once?

OpenStudy (anonymous):

8/9

OpenStudy (anonymous):

There ya go. So which has the higher probability of success?

OpenStudy (anonymous):

b does

OpenStudy (anonymous):

And you're done! :)

OpenStudy (anonymous):

awesome thank you

OpenStudy (anonymous):

could i possibly ask you one more question

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