Question

Part A: Solve F = 9/5= C + 32 for C.
Part B: Determine the value of C when F = 10 °F.
Part C: Solve -np - 70 > 40 for n. Show your work

Answer 1

Part A:9/5c+32=F

-32 to both sides

9/5c=F-32

this is as far as I got in part A I don't know what I should do next

Answer 2

multiply both sides by \(\frac{5}{9}\)

Answer 3

you can even leave the parentheses there and write
\[C=\frac{5}{9}(F-32)\]

Answer 4

O okay cool, thanks! Now can you help me with part B and C?

Answer 5

now that you have \[C=\frac{5}{9}(F-32)\] if \(F=10\) you can compute
\[C=\frac{5}{9}(10-32)\]

Answer 6

you okay with that?

Answer 7

Yes Okay but for part C is it even really related to part A and B at all

Answer 8

no it isn't but we can do that as well

Answer 9

oh actually we can't!

Answer 10

we can start with \[ -np - 70 > 40\] add \(70\) and get
\[-np>110\]but after that we cannot solve for \(n\)

Answer 11

the reason you cannot solve for \(n\) is that you do not know if \(p\) is positive or negative
you want to divide by \(-p\) but you cannot, because if \(-p>0\) you leave the inequality alone, but if \(-p<0\) you have to switch the inequality

Answer 12

O okay that makes sense....thank you bunches

Answer 13

welcome bunches