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OpenStudy (anonymous):
let I = ∫cos^-1(x)dx
let u = cos^-1(x), then du = -1/sqrt(1-x^2)
let dv = dx, then v = x
and substitute into the integration by parts formula, it should simplify down to:
I = xcos^-1(x) + ∫x/sqrt(1-x^2)dx
now let u = 1-x^2, then du = -2xdx, and xdx = -1/2du
I = xcos^-1(x) -1/2 ∫du/sqrt(u)
I = xcos^-1(x) -sqrt(u) + c
I = xcos^-1(x) -sqrt(1-x^2) + c
OpenStudy (anonymous):
thanks
hartnn (hartnn):
@╰☆╮Openstudier╰☆╮
whats the source ??
OpenStudy (sidsiddhartha):
copied from yahoo lol @@╰☆╮Openstudier╰☆╮
OpenStudy (anonymous):
Yes i forgot to mention i took it from yahoo answers
I know only differentiatiom not integration
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hartnn (hartnn):
its always good to cite the source, else its called plagiarism! which is against the code of conduct.
OpenStudy (sidsiddhartha):
u dont need to know integration from 10th grade for IIT @╰☆╮Openstudier╰☆╮
OpenStudy (anonymous):
We r learning it tommorow!
OpenStudy (sidsiddhartha):
by the way u are from ?@╰☆╮Openstudier╰☆╮
OpenStudy (anonymous):
I am from mumbai u?
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OpenStudy (sidsiddhartha):
live in kharagpur but from kolkata
OpenStudy (anonymous):
u r an iitian
OpenStudy (sidsiddhartha):
studying in 3rd year
hartnn (hartnn):
b. tech in ... ?
OpenStudy (anonymous):
i think hartn is too from kharagpur
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