Question

can anyone help me with this question please?

Answer 1

find the vaule ofX

Answer 2

http://www.mathsisfun.com/geometry/triangles-interactive.html <--- click on "isosceles" button to make the triangle an isosceles triangle

move about any of the points, notice as you move the points, 2 sides remain equal
notice what happens to the angles where those equal sides end

Answer 3

They are equal right so would x be 93.5?

Answer 4

well if the 2 legs are equal, that means

Answer 5

I have no idea i am really struggling here

Answer 6

so the angles where they extend to, are also equal
recall that all internal angles in a triangle add up to 180 degrees so \(\bf 93.5^o+E^o+D^o=180^o\implies E^o+D^o=180^o-93.5^o
\\ \quad \\
E^o=D^o\qquad thus\qquad E^o+E^o=180^o-93.5^o\\ \quad \\\implies 2E^o=180^o-93.5^o

E^o=\cfrac{180^o-93.5^o}{2}\)

Answer 7

\(\bf 93.5^o+E^o+D^o=180^o\implies E^o+D^o=180^o-93.5^o
\\ \quad \\
E^o=D^o\qquad thus\qquad E^o+E^o=180^o-93.5^o
\\ \quad \\
\implies 2E^o=180^o-93.5^o\implies
E^o=\cfrac{180^o-93.5^o}{2}\)

Answer 8

anyhow, if you subtract the known angle from 180, you'd be left with a quantity
divide that by 2, since the other 2 angles are equal, so each take half

Answer 9

Thank you so much i was so confused about the two you were alot of help

Answer 10

yw