two numbers whose product is 64 and the sum is 8

Question

solomonzelman · Answer

$\Huge\color{green}{ \rm       a \times b =64	 }$
$\Huge\color{green}{ \rm       a + b =8	 }$

solve, doesn't matter which one is which.

solomonzelman · Answer

NO

solomonzelman · Answer

Look at what you wrote again.

solomonzelman · Answer

So, you see what your mistake is ?

anonymous · Answer

let 2 numbers be x and y
xy=64
sum = f(x) = x+y = x+64/x
now minimize f(x)

anonymous · Answer

Yes,

solomonzelman · Answer

Anyway, ...

$\Huge\color{red}{ \it       a + b =8	 }$
$\Huge\color{red}{ \it       a  =8-b	 }$

$\Huge\color{red}{ \it       (b-8) \times b =64	 }$
$\Huge\color{red}{ \it       b^{2}-8b =64	 }$
$\Huge\color{red}{ \it       b^{2}-8b +64=0 }$

solve using the quadratic formula, ....

solomonzelman · Answer

the last equation is $\Huge\color{red}{ \it       b^{2}-8b -64	=0 }$