Question

WALK ME THROUGH STEPS

Determine the zeros of the quadratic function f(x)=x^2+5x-6. Factor & Zero Product Property

Answer 1

did you factor it?

Answer 2

i dont know how ?

Answer 3

can you find the factors of 6...

Answer 4

1-6 and 3-2

Answer 5

yup good
now express the coefficient of x which is 5 here in terms of the factors u found..

Answer 6

I got lost

Answer 7

why...

Answer 8

now express the coefficient of x

Answer 9

you found the factors of 6 ..
like 1,6 & 3,2

Answer 10

yea then

Answer 11

now
5= 3+2
5= 6-1

if we use 5=3+2 then (3*2=6 , but the constant term free from x is -6)
use 5 =6-1 as (here 6* -1 = -6)

so we can rewrite f(x)=x^2+5x-6
as f(x)=x^2+(6-1)x-6
f(x) =x^2 +6x -x -6...
i hope you can follow...

Answer 12

I got lost again how did you get f(x) = x^2 +6x -x -6

Answer 13

given f(x)=x^2+5x-6
so f(x)=x^2+(6-1)x-6 [ noe 5 i have expressed as (6-1) ]
now simplify
you may have then x^2 +6x -x -6

Answer 14

now try to take out common terms..
f(x) = x^2 +6x -x -6
f(x) =x(x+6) -1(x+6)
again (x+6) is common
f(x)= (x+6)(x-1)

Answer 15

thank you doesn't it bring back to

Answer 16

yup it should bring back
but you need not simplify it again but you have to find factors....