\(\normalsize \color{black}{ \bf sin^2(x)=1/1+cot^2(x) }\)
as you have worked out already,
\(\normalsize \color{black}{ \bf sin^2(x)=1/sec^2(x) }\)
\(\normalsize \color{black}{ \bf sin^2(x)=cos^2(x) }\)
No.. IT is NOT an identity.....
OpenStudy (anonymous):
i understand it is this computer program we are using
OpenStudy (anonymous):
my bad, hold on
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OpenStudy (anonymous):
thanks for your time
OpenStudy (anonymous):
\(\normalsize \color{black}{ \bf sin^2(x)=1/1+cot^2(x) }\)
\(\normalsize \color{blue}{ Rule:~\bf 1+cot^2(x)=csc^2(x) }\)
so it IS an identity, sorry.
OpenStudy (anonymous):
;)
OpenStudy (anonymous):
you get the idea though... that's the main thing.
OpenStudy (anonymous):
sin^2(x)=1/csc^2(x)=1/1+cot^2(x)
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OpenStudy (anonymous):
sweet
OpenStudy (anonymous):
yes.... :)
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
you welcome.. I'll try not to confuse you again if we hopefully meet again.