Question

Will fan and medal please help!!

1. What is the area of the trapezoid? The diagram is not drawn to scale. (will attach image)
14 cm^2
20cm^2
38cm^2
56cm^2

Answer 1

@phi
@mathmale
@Hero
can you guys help?

Answer 2

I know the area of each of the triangles on the sides are 10 each, so 20 in all. and I'm thinking the middle part is a square, so 9^2 = 81. Then 81 + 20 = 101 but 101cm^2 isn't a answer.

Answer 3

I see this trapezoid is nice and symmetric (the two ends have identical dimensions).

First of all, what is the formula for the area of a trapezoid, given the height of the trap. and the (2 different) legs of the trap?

A = ( ---------- ) ( )

Answer 4

Ohhhh i'm dum lol, forgot about the formula for the area of a trapezoid :/
It's A = a+b/2 right? I forgot it.

Answer 5

Never mind, I googled it and found it to be:
\[\frac{ a + b }{ 2 }h\]

Answer 6

So it would be:
\[A = \frac{ 19 + 9 }{ 2 }(4)\]

Answer 7

That would be correct if only you'd enclose that ' a + b ' within parentheses and include the height of the trapezoid. Try again, please. Use the Draw utility, below, if necessary.

Yes: That formula from Google is correct. Notice that you MUST combine a and b BEFORE you divide by 2; that's why I'm picky about wanting you to enclose ' a+b' inside parentheses.

Answer 8

\[A = 56cm^{2}\]

Answer 9

OK: What is the height of your trap?
What are the two (different) sides of your trap?

Answer 10

Thanks! I had forgotten there was a formula for a trapezoid.

Answer 11

H = 4, Base 1 = 9, Base 2 = 19

Answer 12

OK. I'll take your word for it. But next time, please show how you got your result.

Answer 13

Ok. Can you help with another?

Answer 14

Certainly, if you post your next question in the "Ask a question" box.