Question

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t^2 +19.6t + 58.8. What is the object's maximum height?
A. 58.8
B. 194.04
C. 78.4
D. 117.6

Answer 1

-4.9t^2 +19.6t + 58.8 = -4.9 (t - 6.) (t + 2.)
-4.9 (t - 6.) (t + 2.)
t (19.6 - 4.9 t) + 58.8
t = -2
t = 6

Answer 2

then what ? plug it in ?

Answer 3

@AravindG