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Mathematics 8 Online
OpenStudy (lovelyharmonics):

polar coordinates

OpenStudy (lovelyharmonics):

Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°.

OpenStudy (anonymous):

First find the distance from the orgin to the point. Use the Pythagorean theorem

OpenStudy (lovelyharmonics):

okay so |dw:1399666621986:dw| so 3^2+(-3)^2=18

OpenStudy (anonymous):

Yep, then take the square root of 18 for the last step of Pythagorean theorem

OpenStudy (lovelyharmonics):

3sqrt2

OpenStudy (anonymous):

Great. Now drawing the triangle which we have just made to the point and fill in all the sides of the triangle, Then find the angle between the horizontal leg and the diagonal leg

OpenStudy (lovelyharmonics):

|dw:1399667089969:dw| and id use \[\frac{ 3\sqrt{2} }{ 90 } = \frac{ -3 }{ x }\] right?

OpenStudy (anonymous):

Excellent. Just replace the 90 with sin(90) as well as replace x with sin(x). Then solve for x

OpenStudy (lovelyharmonics):

so sin270=sin3sqrt2x?

OpenStudy (anonymous):

X=Sin^-1(-3*sin(90))/3*sqrt(2)))

OpenStudy (lovelyharmonics):

my calculator wont do that though.....

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