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OpenStudy (lovelyharmonics):
Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°.
OpenStudy (anonymous):
First find the distance from the orgin to the point. Use the Pythagorean theorem
OpenStudy (lovelyharmonics):
okay so
|dw:1399666621986:dw|
so 3^2+(-3)^2=18
OpenStudy (anonymous):
Yep, then take the square root of 18 for the last step of Pythagorean theorem
OpenStudy (lovelyharmonics):
3sqrt2
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OpenStudy (anonymous):
Great.
Now drawing the triangle which we have just made to the point and fill in all the sides of the triangle,
Then find the angle between the horizontal leg and the diagonal leg
OpenStudy (lovelyharmonics):
|dw:1399667089969:dw|
and id use \[\frac{ 3\sqrt{2} }{ 90 } = \frac{ -3 }{ x }\]
right?
OpenStudy (anonymous):
Excellent. Just replace the 90 with sin(90) as well as replace x with sin(x).
Then solve for x
OpenStudy (lovelyharmonics):
so sin270=sin3sqrt2x?
OpenStudy (anonymous):
X=Sin^-1(-3*sin(90))/3*sqrt(2)))
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