When you have 13pi/3 -2pi , why do you get 7pi/3? Wouldn't it be 11pi/3? I am so confused.
what is 13/3 - 2 ?
since 3/3 = 1, this can be written as: 13/3 - 3/3 - 3/3 (13 - 3- 3)/3
i see where you got the 7 from I just understand why you did 3/3. Does it have something to do with having to have the same denominators in order to subtract?
its simpler for us to work the subtraction yes. common denominators place all the values we are to work with on a common playing field. 13/3 and 2/1 , i say are not wearing the same pants and we have to redress them
13/3 is not equal to 13 13-2 = 11, is what you prolly saw in your mind; but by doing that you make up your own problem by changing 13/3 into 13
So what happend to the 2pi in the midst of all this?
pi is pi is pi ... we factored it out and worked the fractions
\[\frac abx+\frac mnx=x(\frac ab+\frac mn)\]
so then it becomes 1 over 1 which you multiply by 3 to get the 3/3 to have the same denominators so you can subtract?
\[\frac{13}{3}-2\]\[1=\frac 33\] \[-1=-\frac 33\] \[-2=-1-1=-\frac 33 - \frac 33\] \[\frac{13}{3}-2=\frac {13}3-\frac 33-\frac 33\]
OR, yeah, we multiply 2 by 3/3
\[\frac{13}{3}-2(1)=\frac{13}{3}-2(\frac 33)\] \[\frac {13}3-\frac 63\]
ok thank you so much! i think i understand it now! i really appreciate your help.
good luck
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