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OpenStudy (zzr0ck3r):
\(\frac{x+2x}{x+1}\)?
OpenStudy (anonymous):
A. 3x/x+1
B. x(x+3)/x+1
C. 4x+1/x+1
D. 2x^2/x+1 would it be D?
OpenStudy (anonymous):
@zzr0ck3r
OpenStudy (zzr0ck3r):
\(\frac{x+2x}{x+1}\) \(\huge ?\)
OpenStudy (anonymous):
A
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OpenStudy (anonymous):
Does x+2x/x+1=(A.) 3x/x+1
OpenStudy (zzr0ck3r):
please answer my question.....x+2x/x+1 is very ambiguous.
I dont know if you mean \(x+\frac{2x}{x}+1\) or \(\frac{x+2x}{x}+1\), or \(\frac{x+2x}{x+1}\). So which one is it?
OpenStudy (zzr0ck3r):
i.e use parenthesis
OpenStudy (anonymous):
the 1st one
OpenStudy (zzr0ck3r):
\(x+\frac{2x}{x}+1\)?
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OpenStudy (anonymous):
yes
OpenStudy (zzr0ck3r):
\(x+\frac{2x}{x}+1=x+2+1=x+3\) this is not one of your options, so im guessing you did NOT mean the 1st one.....
OpenStudy (zzr0ck3r):
the only one that makes sense to your answers is \(\frac{x+2x}{x+1}\)
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OpenStudy (zzr0ck3r):
\(x+\frac{2x}{x+1}\) does not look like \(x+\frac{2x}{x}+1\) to me:P
OpenStudy (zzr0ck3r):
ok
\(x+\frac{2x}{x+1}\)
we need a common denominator which will be \(x+1\) so multiple the first term (top and bottom) by (x+1)
\(x+\frac{2x}{x+1}=x\frac{x+1}{x+1}+\frac{2x}{x+1}=\frac{x(x+1)}{x+1}+\frac{2x}{x+1}=\frac{x^2+x}{x+1}+\frac{2x}{x+1}=\frac{x^2+x+2x}{x+1}=\\\frac{x^2+3x}{x+1}=x\frac{x+3}{x+1}\)