Question

f(x)=5x^2+2 what is the vertex?

Answer 1

since there is no \(x\) term the first coordinate of the vertex is \(0\)

Answer 2

@satellite73 would it be 0,2?

Answer 3

and the axis of symmetry is 2?

Answer 4

ohh okay thanks! to graph it, do i just plug any numbers into x to get y value?

Answer 5

just 0?

Answer 6

@Chad123

Answer 7

Let me start all over again

Answer 8

Y=5x^2+2

Point (x,y) is your vertex

Let a=5 and b=0 since there is no term for b

X=-b/2a = -0/2(5) = 0/10 = 0

X=0 is your line of symmetry

To find your vertex replace x with 0 in your function and solve for y

Y=5(0)^2+2
Y=2

(0,2) is your vertex

Answer 9

ohh that makes sense :) thanks so much! and is there a specific formula to find the min/max?