Question

I'm stock aging!
solve,
2/p+1 - 1/p-1 = 2p/p^2-1
thanks!

Answer 1

stock aging is funny

Answer 2

\(\frac{2}{p+1}-\frac{1}{p-1}=\frac{2p}{(p^2-1)}\)?

Answer 3

yes!

Answer 4

use the difference of squares then find a comon denom

\(\frac{2}{p+1}-\frac{1}{p-1}=\frac{2p}{(p^2-1)}\iff\frac{2}{p+1}-\frac{1}{p-1}=\frac{2p}{(p-1)(p+1)}\iff\\\frac{2(p-1)}{(p+1)(p-1)}-\frac{1(p+1)}{(p-1)(p+1)}=\frac{2p}{(p^2-1)}\iff\\2(p-1)-(p+1))=2p\iff2p-2-p-1=2p\iff-3=p\)