Question

For triangle ABC side a=19, side b=19 and angle A=141° find c to the nearest whole number.

Thanks to whoever helps me out :)

Answer 1

well to find the c side of the triangle use Pythagorean theorem
\[a^{2}+b ^{2}=c ^{2}\]
So if\[a=19~and~b=19\]
Then\[19^{2}+19^{2}=38^{2}\]


So i would assume that side c is 38 but i could be wrong.