Question

Solve the triangle.

A = 19°, C = 102°, c = 6

Answer 1

i got B = 59°, a ≈ 2, b ≈ 5.3

Answer 2

just checking my answer

Answer 3

59 is of course correct

Answer 4

\[\frac{6}{\sin(102)}=\frac{a}{\sin(19)}\] so
\[a=\frac{6\sin(19)}{\sin(102)}\] is that about 2?

Answer 5

yeah looks like about 2

Answer 6

yay

Answer 7

want me to check the last one? probably right as well

Answer 8

no thts okay thank u

Answer 9

I previously entered some figures here but I deleted those because I was thinking (incorrectly) this was two angles and an included side.
59° side 6 19° IS an ASA congruency problem and the remaining sides are:

5.2579
1.997