Question

I need to find the focus on the parabola of this equation. Fan and medal for best answer!

Answer 1

easier to write it as
\[32y=(x-2)^2\] this tells you the vertex is \((2,8)\)

Answer 2

now that it looks like
\[4py=(x-h)^2\] you know \(p=8\)

Answer 3

the focus is therefore \(8\) units directly above the vertex

Answer 4

i had a typo there, i meant the vertex is \((2,0)\) not \((2,8)\)
the focus, however, is \((2,8)\) 8 units above \((2,0)\)

Answer 5

That doesn't appear as one of my choices though @satellite73

Answer 6

Wait isn't 36/4 = 9 and not 8?