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Mathematics 7 Online
OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

In a random sample of 1000 exams, the average score was 500 points with a standard deviation of 80 points. 16. Find the interval about the sample mean that has a 1% level of confidence. a. 499-501 b. 479-520 c. 495-505 d. 493-507 17. Find the interval about the sample mean such that the probability is 0.90 that the mean number lies within the interval. a. 499-501 b. 495-505 c. 496-504 d. 368-632 18. Find the probability that the mean score of the population will be less than five points from the mean score of the sample. a. 95.5% b. 38.3% c. 98.8% d. 62.5% 19. Find the probability that the true mean is between 495 and 500. a. 95% b. 47.75% c. 95.5% d. 68.3%

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

were you able to get anywhere with 16?

jimthompson5910 (jim_thompson5910):

I think they want a confidence interval

jimthompson5910 (jim_thompson5910):

so you need to compute the lower and upper bounds (L and U) L = xbar - z*sigma/sqrt(n) L = xbar + z*sigma/sqrt(n)

jimthompson5910 (jim_thompson5910):

xbar is the sample mean z is the critical value based on the level of confidence sigma = standard deviation n = sample size

OpenStudy (anonymous):

is z=1?

jimthompson5910 (jim_thompson5910):

no you have to determine z based on the 1% confidence level

OpenStudy (anonymous):

how do i do that?

jimthompson5910 (jim_thompson5910):

unfortunately the table I gave you only goes down to 50% confidence level

jimthompson5910 (jim_thompson5910):

let me try to find a better one

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

are you sure it's not alpha they're talking about?

jimthompson5910 (jim_thompson5910):

it just seems really really odd to have CL = 1%

OpenStudy (anonymous):

yeah it says 1% level of confidence

jimthompson5910 (jim_thompson5910):

so that means 100 - 1 = 99% of the distribution is in the two tails each tail has 99/2 = 49.5%

jimthompson5910 (jim_thompson5910):

have a look at this table http://www.math.upenn.edu/~chhays/zscoretable.pdf where on page 1 (towards the bottom) is there a value that's close to 0.495 ?

OpenStudy (anonymous):

ya there is 0.4960

jimthompson5910 (jim_thompson5910):

what z score corresponds to that

OpenStudy (anonymous):

how do i do that again? z=(x-mean)/standard deviation is that the formula?

jimthompson5910 (jim_thompson5910):

no look at the table and where you found 0.4960 using that table, what is the z-score?

OpenStudy (anonymous):

0.01 ?

OpenStudy (anonymous):

or is it -0.0 ? haha sorry @jim_thompson5910

jimthompson5910 (jim_thompson5910):

that's part of it. Look at the top of the column to finish it off

OpenStudy (anonymous):

what? is it 0.01

jimthompson5910 (jim_thompson5910):

so that means P(-0.01 < z < 0.01) = 0.01 roughly

jimthompson5910 (jim_thompson5910):

the critical value is z = 0.01

jimthompson5910 (jim_thompson5910):

Now evaluate L = xbar - z*sigma/sqrt(n) U = xbar + z*sigma/sqrt(n)

OpenStudy (anonymous):

ok so L=500-0.01*80/root(1000) U=500+0.01*80/root(1000(

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

L=499.9747018 U=500.0252982

OpenStudy (anonymous):

So 16. A?

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

that's the thing, it's close to A, but rounding those two give you L = 500, U = 500 kind of a lousy confidence interval if you ask me

jimthompson5910 (jim_thompson5910):

I guess A is the best choice to go with though

OpenStudy (anonymous):

ok thank you so much!!! I dont need help with the others. THANK YOU :)

jimthompson5910 (jim_thompson5910):

ok I'm glad you figured those out

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