Question

lim 2x³-x²+7x-3 =
x->∞ 2-x+5x²-4x³

Answer 1

http://www.wolframalpha.com/

Answer 2

\[\large \lim \limits_{x\to \infty}~ \dfrac{2x^3-x^2+7x-3}{2-x+5x^2-4x^3}\]

Answer 3

like this ?

Answer 4

yes

Answer 5

divide top and bottom by x^3
as \(x\to \infty, \frac{1}{x}\to 0 \)

Answer 6

\[\lim \limits_{x\to \infty}~ \dfrac{2x^3-x^2+7x-3}{2-x+5x^2-4x^3} = \lim \limits_{\frac{1}{x}\to 0}~ \dfrac{2-\frac{1}{x}+\frac{7}{x^2}-\frac{3}{x^3}}{\frac{2}{x^3}-\frac{1}{x^2}+\frac{5}{x}-4} \\ = \dfrac{2-0+0-0}{0-0+0-4} = \dfrac{-1}{2}\]

Answer 7

I caught \[2x^{3} and -4x^{3} = -1/2\]

Answer 8

taking the ratio of leading coefficients works too^

Answer 9

yes

Answer 10

thanks

Answer 11

yw

Answer 12

can help me more one question

Answer 13

\[\frac{ x }{ \sqrt{x+1} }\]

Answer 14

limite infinity positive

Answer 15

http://www.wolframalpha.com/input/?i=%5Clim+x+%5Cto+%5Cinfty%2B+x%2Fsqrt%28x%2B1%29