Question

Did I do this right?

Answer 1

Here is the equation:\[2\sqrt{10}+\sqrt{10}-5\sqrt{10}\]

Answer 2

I actually did it wrong so I don't know the answer...

Answer 3

Think of \(\Large \sqrt{10}\) as a variable

Answer 4

it is not an equation (no equal sign). it is called an expression

add up how many "root tens" you have

Answer 5

begin by taking sqrt of 10 out as common factor.

Answer 6

so you can replace it with say x to get

2x + x - 5x

Answer 7

what do you get when you combine like terms for 2x + x - 5x

Answer 8

10x^3

Answer 9

no, you are adding or subtracting. How about this
2 shoes + 1 shoe take away 5 shoes

how many shoes?

Answer 10

Oh sorry I thought it was multiplying :( It would be -2 shoes...

Answer 11

Or just-2x

Answer 12

or as jim showed,
2 x's + 1 x take away 5 x's

how many x's

you have 3 x's take away 5 x's = -2 x's
written -2x

same for sqr(10)

Answer 13

2 sqr(10) + sqr(10) - 5 sqr(10)

how many sqr(10) do you have ?

Answer 14

3

Answer 15

?
you should get -2 sqr(10)
It is the same problem (same idea) as for shoes or for x

Answer 16

Is that the answer?

Answer 17

The answer is getting the idea.

if you can do
2 shoes + 1 shoe take away 5 shoes
and get -2 shoes

and you can do
2 x + x - 5 x (which means 2 x's plus 1 x take away 5 x's)
and get -2 x

then you can do
2 sqr(10) + sqr(10) - 5 sqr(10)

Answer 18

Okay...so what's next?

Answer 19

add up how many sqr(10) 's you have

2 sqr(10) plus one more sqr(10), take away 5 sqr(10)'s
how many sqr(10)'s do you have ?

Answer 20

Oh I get what you're doing! Sorry I was a little confused...\[-2\sqrt{10}\]

Answer 21

math is not really *that* hard. Just get the idea.

Answer 22

I'd just do it this way

Start with

\[\Large 2\sqrt{10}+\sqrt{10}-5\sqrt{10}\]

Let \(\Large x = \sqrt{10}\) which allows us to get

2x + x - 5x

Then combine like terms to get -2x

After you've simplified as much as possible, replace x with \(\Large \sqrt{10}\) to get

-2x ---> \(\Large -2\sqrt{10}\)

Answer 23

Yeah I know...we are not learning this yet but I just want to go ahead of my class :)

Answer 24

We are going to learn this tomorrow but I just like to learn things ahead of everyone :)

Answer 25

Thanks for answering everyone :)

Answer 26

another way to think about it is use the laws of arithmetic.
the distributive law says
ab + ac = a(b+c)

it works for 3 terms, so you could do this
\[ 2 \sqrt{10} + 1\sqrt{10}- 5\sqrt{10}= (2+1-5)\sqrt{10} \\= -2 \sqrt{10}\]

Answer 27

That's a good way too...thank you :)

Answer 28

yw