Question

If \(\tan (\pi \cos \theta) = \cot (\pi \sin \theta) \) , \(\theta \in \left( 0, \cfrac{\pi}{2} \right)\) , then \(\cos \left( \theta - \cfrac{\pi}{4} \right) = ? \)

(Again, not a challenge)

Answer 1

If \(\tan (\pi \cos \theta) = \cot (\pi \sin \theta) \) , \(\theta \in \left( 0, \cfrac{\pi}{2} \right)\) , then \(\cos \left( \theta - \cfrac{\pi}{4} \right) = ? \)

(Again, not a challenge)

Answer 2

What I like about this question is that we have tan and cot here, we can use them...

or put sin and cos there instead of tan and cot.

Answer 3

\(\cfrac{\sin (\pi \cos \theta) }{\cos (\pi \cos \theta) } = \cfrac{\cos (\pi \sin \theta)}{\sin (\pi \sin \theta) } \)

Answer 4

\(\Large \tan(A+B) = ...
have you come across this formula ?\)

Answer 5

have you tried it yet kush?

Answer 6

@mukushla yeah, these questions are in my notebook ... list of questions in which I need help.

I tried it a lot. Tried to simplify, but I don't get anything.

Answer 7

Do you want me to put that here? But, I really didn't get anything right.

Answer 8

if tan A tan B = 1
A+B = pi/2