Find Pk + 1for the given Pk: Pk = 2k^2
A. 2k^2 - 2
B. 2(k +1) +6k
C. Pk + 1
D. 2(k +1)^2

Question

Find Pk + 1for the given Pk: Pk = 2k^2 
	A.	2k^2 - 2
	B.	2(k +1) +6k
	C.	Pk + 1
	D.	2(k +1)^2

anonymous · Answer

im having trouble with this someone please help

anonymous · Answer

@jigglypuff314  @Harsha19111999 @Hero @wheelchairgirl @Whitemonsterbunny17 @ganeshie8  Can you Guys help:))

jigglypuff314 · Answer

Are there any parenthesis involved?
like P(k) = 2k^2 ?
and  P(k+1)

anonymous · Answer

no

jigglypuff314 · Answer

The only thing I could think of would be
Addition Property of Equality
but that's not an answer choice
so, I'm stuck
sorry :(

anonymous · Answer

same, but thak you for trying :)

anonymous · Answer

@jigglypuff314  There's no appology needed at least you took the time out of everyone i tagged and Attempted to help @ynnhojgomez ..So thanks hehe:)) Have a Nice Day!!

hero · Answer

@ynnhojgomez, Did it ask to find P(k + 1) or Pk + 1

anonymous · Answer

pk+1

jigglypuff314 · Answer

......................
if you insist...
but there is an answer if it is P(k+1)
replace the k in  2k^2
with (k+1)
and you'll get one of the answer choices
if you're gonna take a guess that'd be it

hero · Answer

If we use P(k + 1) we get one of the answer choices
If we use Pk + 1 we get none of the answer choices

anonymous · Answer

yeah i was having trouble with the fact that it had no parenthesis so i guess its supposed to have parenthesis

anonymous · Answer

thank you @jigglypuff314 it was right :D