Question

How do you solve: logbase5 (square root of x+3) = logbase5 (4)?

Answer 1

this means your insides have to be equal

Answer 2

\[\log_{5} (\sqrt{x+3})=\log_{5} (4)\] <- thats a better way to view the equation.

Answer 3

Since y=log_5(x) is a one to one function
if you have f(a)=f(b)
then this implies a=b

Answer 4

like basically i'm telling you that \[\sqrt{x+3}=4 \text{ now solve }\]

Answer 5

Ohhh thank you. I accidentally put the wrong exponent when trying to get rid of the square root, which through off my calculations. Thank you :D

Answer 6

coolness