Question

simplify 1+sinx/cosx+cosx/1+sinx

Answer 1

\[\frac{1+\sin x}{\cos x} + \frac{\cos x}{1 + \sin x}\] right?

Answer 2

take alcium
[(1+sinx)(1+sinx)+(cosx.cosx)]/(cosx.(1+sinx))

Answer 3

[1+sin(x)^2+2sinx+cosx^2]/cosx(1+sinx)
[1+2sinx+(sinx^2+cosx^2)]/cosx(1+sinx)..
as (sinx^2+cosx^2)=1
[1+2inx+1]/cosx(1+sinx)
(2+2sinx)/cosx(1+sinx)
2(1+sinx)/cosx(1+sinx)
2/cosx
2.secx
answer

Answer 4

is that fine now @antonyo