OpenStudy (anonymous):

Since the opening night, attendance at Play A has increased steadily, while attendance at Play B first rose and then fell. Equations modeling the daily attendance y at each play are shown below, where x is the number of days since the opening night. On what day(S) was the attendance the same at both plays? what was the attendance? Play A: y = 16x + 150 Play B: y = -x^2 60x - 10 answer choices: The attendance was the same on day 40. The attendance was 790 at both plays that day. The attendance was the same on day 4. The attendance was 214 at both plays that day. The attendance w

4 years ago
OpenStudy (anonymous):

@triciaal

4 years ago
OpenStudy (triciaal):

set the y's equal and solve

4 years ago
OpenStudy (anonymous):

okay

4 years ago
OpenStudy (triciaal):

this will give the day the attendance the same is that a "+ 60x"

4 years ago
OpenStudy (triciaal):

16x + 150 = -x^2 + 60x -10 x^2 -60x +16x + 150 + 10 = 0

4 years ago
OpenStudy (anonymous):

so the answer is: the attendance was never the same on both plays?

4 years ago
OpenStudy (anonymous):

can I ask another question @triciaal

4 years ago
OpenStudy (triciaal):

sure but before you go to the next ? how did you decide this one

4 years ago
OpenStudy (anonymous):

Because of the step which shows it was 0, that meant that the answer would be none, and they never did. that was the last answer choice, it just did fully come out.

4 years ago
OpenStudy (triciaal):

did you plug the choices and check you did not verify +60x

4 years ago
OpenStudy (anonymous):

so your saying I'm wrong?

4 years ago
OpenStudy (triciaal):

i am saying did not find x and therefore did not actually check to confirm did not plug the given numbers to check

4 years ago
OpenStudy (anonymous):

Wait so you don't know if I'm right? I'm confused now, and I don't usually go back and check like that how would I do that?

4 years ago
OpenStudy (triciaal):

I set the y's equal to find the value of x but the eqn written was not clarified so i did not solve for x; you did not answer

4 years ago
OpenStudy (triciaal):

what is the next question?

4 years ago
OpenStudy (anonymous):

oh so was I right? or not?

4 years ago
OpenStudy (anonymous):

let me write the next question

4 years ago
OpenStudy (triciaal):

the answer is b it I use +60x

4 years ago
OpenStudy (triciaal):

look at the question did you miss a plus sign that's what i need to know and you did not answer

4 years ago
OpenStudy (anonymous):

yes on Play B

4 years ago
OpenStudy (anonymous):

there was a missing + sign ur right

4 years ago
OpenStudy (anonymous):

14. What ate tje solutions to the system? y = x^2 - 6x + 7 y = -x + 13 (-1, 14) and (6, 14) (-1, 7) and (6, 14) (-1, 13) and (6, 7) no solution.

4 years ago
OpenStudy (anonymous):

@triciaal

4 years ago
OpenStudy (triciaal):

set the y's equal

4 years ago
OpenStudy (triciaal):

x^2 -6x + 7 = -x + 13

4 years ago
OpenStudy (triciaal):

add x -13 to each side

4 years ago
OpenStudy (triciaal):

group like terms

4 years ago
OpenStudy (triciaal):

x^2 -5x -6 = 0

4 years ago
OpenStudy (triciaal):

what are the factors of -6 that add to -5

4 years ago
OpenStudy (triciaal):

lets use -6 and + 1 x^2 - 6x + x -6 = 0 x(x + 1)-6(x+1) = 0 (x+1)(x-6)=0

4 years ago
OpenStudy (anonymous):

hmm...

4 years ago
OpenStudy (anonymous):

okay

4 years ago
OpenStudy (triciaal):

x= -1, x = 6 you have the x value put in the 2nd eqn and find y

4 years ago
OpenStudy (triciaal):

i dont see the ans I got (-1, 14) and (6, 7)

4 years ago
OpenStudy (anonymous):

its there, its the first option

4 years ago
OpenStudy (triciaal):

your first option has (6, 14)

4 years ago
OpenStudy (anonymous):

oops haha, on my test it says: (-1, 14) and (6, 7) I copied wrong lol its supposed to be the first choice.

4 years ago
OpenStudy (anonymous):

can we do another?

4 years ago
OpenStudy (triciaal):

thank you

4 years ago
OpenStudy (triciaal):

last one for now i have to get going

4 years ago
OpenStudy (anonymous):

haha no prob

4 years ago
OpenStudy (anonymous):

okay

4 years ago
OpenStudy (anonymous):

15. Simplify the radical expression. \[\sqrt{72} \] \[2\sqrt{6}\] \[6\sqrt{2}\] \[-6\sqrt{2}\] 12

4 years ago
OpenStudy (anonymous):

alright there it is and I will be back in just a moment

4 years ago
OpenStudy (triciaal):

what are the prime factors of 72

4 years ago
OpenStudy (triciaal):

rt 72 = rt of 2*2*2*3*3 2*3 *rt2 = 6rt2

4 years ago
OpenStudy (triciaal):

remember rt2 *rt2 = 2 and rt3*rt3 = 3

4 years ago
OpenStudy (triciaal):

with practice you will learn to factor out perfect sq 72 = 4 * 2 * 9 72 = 2*36 perfect sqs 4,9, 36

4 years ago
OpenStudy (triciaal):

choice c nonetheless later

4 years ago
OpenStudy (anonymous):

thank you!! have a nice day sorry i had to leave for a moment.

4 years ago