Question

There are 4 pitchers, 3 catchers, 8 outfielders, and 10 infielders on a baseball team. How many permutations of players can be on the field at any given time? Note that there can only be 1 pitcher, 1 catcher, 4 infielders, and 3 outfielders on the field at any given time.

Answer 1

You would multiply all of the numbers together

Answer 2

Really? I assumed that since it was a permutation, you would do something like\[\frac{ 25! }{ 3!4!8!10! }\] That way you're taking into account the multiple players.

Answer 3

Oh yea sorry I read that wrong

Answer 4

Is that how you would do it? I'm trying to make sure before I write anything down.

Answer 5

Yea thats how I would do it

Answer 6

Okay, thank you

Answer 7

Ur welcome

Answer 8

no

Answer 9

4*3*10!/6! * 8!/5!
if the placement of players doesnt matter then
4*3*10!/(6!*4!)*8!/(5!*3!)

Answer 10

@dan815 it is a permutation, the placement matters because heach individual player has a spot