Question

g(x)=(x-2)(x-4), x bigger or equal than 3
Find inverse function

Answer 1

g(x)=(x-2)(x-4)
y=x^2-6x+8
now complete a a square

Answer 2

y +\((\frac{-6}{2})^2\) =x^2-6x+8 +\((\frac{-6}{2})^2\)

Answer 3

(x+9)^2-1

Answer 4

mmm u made a small mistake

Answer 5

when u add (6/2)^2
y=x^2-6x+8+(6/2)^2-(6/2)^2
y=x^2-6x+ (3)^2-(3)^2 +8
y=x^2-6x+ (3)^2-9 +8
so it will be :-
y=x^2-6x+ (3)^2-1
y=(x-3)^2 -1

Answer 6

@eric_d got it ?

Answer 7

okay, jst realised

Answer 8

ok so nw can u find the inverse ?

Answer 9

I don't know

Answer 10

ohh its ok :D
so u have
y=(x-3)^2-1
the inverse means to write the function with respect to y that means solve for x
( try to make x in one side by its own and the other side includs y)

Answer 11

ok

Answer 12

understood

Answer 13

y=(x-3)^2-1

step 1:-
y+1=(x-3)^2

stwp 2 :-
\(\pm \sqrt{y+1}= x-3 \)

Answer 14

That will be the final answer rite

Answer 15

@ikram002p

Answer 16

yeah right !

Answer 17

Thanks @ikram002p

Answer 18

np :)

Answer 19

Can u fan me
So, I can message u.... @ikram002p

Answer 20

done :D

Answer 21

Thanks