Question

3^2y+1-28(3^y)+9=0
Find real values of y

Answer 1

\[3^{2y+1}-28(3^y)+9=0~~?\]

Answer 2

ya

Answer 3

\[3(3^{2y})-28(3^y)+9=0\]
Let \(x=3^{y}\), then \(x^2=(3^y)^2=3^{2y}\). So what you really have is a quadratic equation:
\[3x^2-28x+9=0\]
Find the solutions for \(x\).

But, keep in mind you want a solution for \(y\). If you happen to get something like \(x=2\), then a solution would be \(3^y=2\) or \(y=\log_32\).

Answer 4

ok thank you very much.

Answer 5

yw