Verify/Establish:
[(1+sec theta)/sec theta)]=[sin^2 theta/(1-cos theta)]
Would it be better to begin from the LHS or the RHS?

Question

Verify/Establish:
[(1+sec theta)/sec theta)]=[sin^2 theta/(1-cos theta)]
Would it be better to begin from the LHS or the RHS?

goformit100 · Answer

RHS and LHS will work.

You procceed from RHS to LHS

anonymous · Answer

Okay, would I go about it be putting sec theta in it's form of 1/cos theta?

goformit100 · Answer

LHS :-

[(1+sec theta)/sec theta)]
= 1/ sec theta + sec theta/sec theta
= (cos theta + 1) = ( 1 + cos theta )

goformit100 · Answer

[sin^2 theta/(1-cos theta)] 
= [(1 - cos^2 theta)/(1-cos theta)] 
= [(1 + cos theta)(1 - cos theta)/(1-cos theta)] 
= (1 + cos theta) ....................= LHS .......................proved

goformit100 · Answer

Okay ?

anonymous · Answer

Okay, I'm just looking over your process. Sorry it's taking me such a long time.

anonymous · Answer

Thank you so much for showing me.

goformit100 · Answer

No worries Ma'am. you can take your own time.

goformit100 · Answer

Welcome it's my pleasure.