Question

a body is falling freely under gravity.How much distance it falls during an interval of time between 1st and 2nd seconds of its motion , taking g=10?

Answer 1

\(\boxed{\boxed{\boxed{\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\\\color{white}{.}\\\Huge\color{blue}{\mathfrak{~~~~Welcome~to~OpenStudy!~\ddot\smile}}\\\color{white}{.}\\\\\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}}}}\)

Answer 2

thanks

Answer 3

do u know the formula
\[S=ut+\frac{ 1 }{ 2 }at ^{2}\]

Answer 4

yes

Answer 5

When a body falls freely, it's initial velocity is 0

Answer 6

ok

Answer 7

Now can u do this ?

Answer 8

u have to calculate S

Answer 9

yes 5*3=15?

Answer 10

how u didi this ?

Answer 11

1/2*10*(1.5)^2

Answer 12

Between 1st and 2nd seconds means that t=2-1=1sec

Answer 13

getting my points ?

Answer 14

i think between 1 & 2=1.5

Answer 15

NO !
interval of time between the 1st and 2nd seconds means a total duration of 2-1 = 1 sec

Answer 16

Suppose second hand of a clock is at 1 sec, then it will take a time of 1 sec to reach at 2nd second....Getting it ?

Answer 17

i m getting you but if i put 1.5 then my answer is right. becoz the answer is 15

Answer 18

I know the answer is 15.....

Answer 19

The body has travelled for a total of 2 seconds

Answer 20

Now if put t=1

Answer 21

It will give us the distance A

Answer 22

If we put 2, it will give us the distance B

Answer 23

But we have to calculate distance C

Answer 24

getting it ?

Answer 25

yes

Answer 26

So can u calculate now ?

Answer 27

10*(2)^2 - 10*(1)^2

Answer 28

got it ?

Answer 29

ok thanks

Answer 30

\(\Huge\text{Anytime !}\)
\(\huge\ddot\smile\)

Answer 31

uh pretty sure, uh got this ?

Answer 32

yes friend

Answer 33

Hello, and A Warm Welcome to Open Study!