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(3x^2 + 2x - 3)(x - 1)
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Multiply every term together. Do you know how?
no im stuck
Okay, I'll walk you through it. Take the first term and separate it from the other two terms in that trinomial. So you have this: (3x^2)(x - 1) Now distribute 3x^2 to x and -1.
is it 3x^2+3x-4?
Not quite, you want 3x^3 - 3x^2.
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uggh...
So you have the next term. 2x. So... 2x(x - 1)
what about this 2x^2-2x
Yup :D
3x^3 - 3x^2 + 2x^2-2x Now the third term must be distributed and added.
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3x^3+x^2-2x
3x^3 - 3x^2 + 2x^2 - 2x Stay at that before you simplify. You still have to do: 3(x - 1)
3x^3-5x-3
3x^3 - 3x^2 + 2x^2 - 2x + 3x - 3 3x^3 - x^2 + x - 3
i give up thanks for your help
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Never give up, you can figure it out. :) Good luck on future problems.
thanks
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